See Socrate on Wiktionary
{
"categories": [
{
"kind": "other",
"name": "有3個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "法語 個人",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "法語專有名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "法語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "法語陽性名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古希臘語的法語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自古希臘語的法語借詞",
"parents": [],
"source": "w"
}
],
"etymology_text": "借自古希臘語 Σωκράτης (Sōkrátēs)。",
"lang": "法語",
"lang_code": "fr",
"pos": "name",
"senses": [
{
"glosses": [
"蘇格拉底"
],
"id": "zh-Socrate-fr-name-c4acD24m"
}
],
"tags": [
"masculine"
],
"word": "Socrate"
}
{
"categories": [
{
"kind": "other",
"name": "意大利語 個人",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語專有名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "意大利語陽性名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有3個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
}
],
"lang": "意大利語",
"lang_code": "it",
"pos": "name",
"senses": [
{
"categories": [
{
"kind": "other",
"name": "古希臘語男性名字的意大利語譯名",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古希臘語的意大利語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自古希臘語的意大利語借詞",
"parents": [],
"source": "w"
}
],
"glosses": [
"男性名字於古希臘語，Σωκράτης (Sōkrátēs)，一般指哲學家蘇格拉底"
],
"id": "zh-Socrate-it-name-OPk-P2VG"
}
],
"tags": [
"masculine"
],
"word": "Socrate"
}
{
"categories": [
{
"kind": "other",
"name": "有3個詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "有詞條的頁面",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "派生自古希臘語的羅馬尼亞語詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "源自古希臘語的羅馬尼亞語借詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "羅馬尼亞語 個人",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "羅馬尼亞語專有名詞",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "羅馬尼亞語詞元",
"parents": [],
"source": "w"
},
{
"kind": "other",
"name": "羅馬尼亞語陽性名詞",
"parents": [],
"source": "w"
}
],
"etymology_text": "借自古希臘語 Σωκράτης (Sōkrátēs)。",
"lang": "羅馬尼亞語",
"lang_code": "ro",
"pos": "name",
"senses": [
{
"glosses": [
"蘇格拉底"
],
"id": "zh-Socrate-ro-name-c4acD24m"
}
],
"tags": [
"masculine"
],
"word": "Socrate"
}
{
"categories": [
"意大利語 個人",
"意大利語專有名詞",
"意大利語詞元",
"意大利語陽性名詞",
"有3個詞條的頁面",
"有詞條的頁面"
],
"lang": "意大利語",
"lang_code": "it",
"pos": "name",
"senses": [
{
"categories": [
"古希臘語男性名字的意大利語譯名",
"派生自古希臘語的意大利語詞",
"源自古希臘語的意大利語借詞"
],
"glosses": [
"男性名字於古希臘語，Σωκράτης (Sōkrátēs)，一般指哲學家蘇格拉底"
]
}
],
"tags": [
"masculine"
],
"word": "Socrate"
}
{
"categories": [
"有3個詞條的頁面",
"有詞條的頁面",
"法語 個人",
"法語專有名詞",
"法語詞元",
"法語陽性名詞",
"派生自古希臘語的法語詞",
"源自古希臘語的法語借詞"
],
"etymology_text": "借自古希臘語 Σωκράτης (Sōkrátēs)。",
"lang": "法語",
"lang_code": "fr",
"pos": "name",
"senses": [
{
"glosses": [
"蘇格拉底"
]
}
],
"tags": [
"masculine"
],
"word": "Socrate"
}
{
"categories": [
"有3個詞條的頁面",
"有詞條的頁面",
"派生自古希臘語的羅馬尼亞語詞",
"源自古希臘語的羅馬尼亞語借詞",
"羅馬尼亞語 個人",
"羅馬尼亞語專有名詞",
"羅馬尼亞語詞元",
"羅馬尼亞語陽性名詞"
],
"etymology_text": "借自古希臘語 Σωκράτης (Sōkrátēs)。",
"lang": "羅馬尼亞語",
"lang_code": "ro",
"pos": "name",
"senses": [
{
"glosses": [
"蘇格拉底"
]
}
],
"tags": [
"masculine"
],
"word": "Socrate"
}
Download raw JSONL data for Socrate meaning in All languages combined (1.4kB)
This page is a part of the kaikki.org machine-readable All languages combined dictionary. This dictionary is based on structured data extracted on 2025-01-03 from the zhwiktionary dump dated 2025-01-01 using wiktextract (eaedd02 and 8fbd9e8). The data shown on this site has been post-processed and various details (e.g., extra categories) removed, some information disambiguated, and additional data merged from other sources. See the raw data download page for the unprocessed wiktextract data.
If you use this data in academic research, please cite Tatu Ylonen: Wiktextract: Wiktionary as Machine-Readable Structured Data, Proceedings of the 13th Conference on Language Resources and Evaluation (LREC), pp. 1317-1325, Marseille, 20-25 June 2022. Linking to the relevant page(s) under https://kaikki.org would also be greatly appreciated.